tag:blogger.com,1999:blog-3862070466581846873.post5386839996672943963..comments2011-01-03T05:45:21.588-07:00Comments on CRMS Calculus 2010: Super sick scribe postBruhttp://www.blogger.com/profile/00445757737038941900noreply@blogger.comBlogger9125tag:blogger.com,1999:blog-3862070466581846873.post-32626989663694270482010-02-10T22:21:59.476-07:002010-02-10T22:21:59.476-07:00JT, nice post, I am not part of this class so as a...JT, nice post, I am not part of this class so as an outsider and calc lover I followed the example very easily and made sense to me, even reminded me of a couple of things that I had forgotten (oh nooooo).<br /><br /><br />Marley, I like your try to tackle the hard problem, try using this formula when doing it. Let a,b be two functions. If you want to take the derivative of a(b) = (a')b + a(b') and in the first line, I don't follow how you got 10(x^2(y)) on one side, you should look at that again.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-3862070466581846873.post-18111524907658395902010-02-10T10:25:27.884-07:002010-02-10T10:25:27.884-07:00Dude thanks for making me the scribe post. I reall...Dude thanks for making me the scribe post. I really like the fact that you used such a large number of equations in your scribe post. For me its super helpful to have a ton of examples to go off of in my learning. So i thought i'd share some more with everyone else.<br /><br />http://www.math.ucdavis.edu/~kouba/CalcOneDIRECTORY/implicitdiffdirectory/ImplicitDiff.html<br /><br />Theres a few practice problems, and expalnation, and some examples.Johnhttps://www.blogger.com/profile/15970027295368822066noreply@blogger.comtag:blogger.com,1999:blog-3862070466581846873.post-62918138462084715252010-02-03T20:43:39.266-07:002010-02-03T20:43:39.266-07:00Hey J-tron, good meaningful coloring and I thought...Hey J-tron, good meaningful coloring and I thought that putting the examples of explicit and implicit equations alone and in bold was a good move. I think one thing that might help you as the equations get more complex is to use equation editor. I know it is a freakin pain but at least for the 2nd example, it could just make things more on the side of eye candy. (Same goes for you Marley). Also, I think that it could have been very helpful to include in the very beginning to use the chain rule and that y' is always alone (ie, no exponents or multiplication by an integer...) in the derivative (or is it?). In my opinion, this is one of the most difficult concepts we have covered so far, and you did a fantastic job of explaining it. However, I think that putting in other examples (not on the wksht) could really help to ingrain this concept into our minds (although, I found a whole bunch easily in the txt book). And personally, I don't feel that including an extraneous picture in hopes of getting an E is necessary to my learning calculus, so thank you for keepin it real.<br />:)dammitimmadhttps://www.blogger.com/profile/17874746889704333355noreply@blogger.comtag:blogger.com,1999:blog-3862070466581846873.post-33638269919173432892010-02-01T07:57:08.266-07:002010-02-01T07:57:08.266-07:00J-tron foteen,
This is a really good scribe p...J-tron foteen,<br /><br /> This is a really good scribe post. It is quite thorough and has a lot of great examples. I mean is there anybody from Calculoplis that doesn't love and appreciate a good calculus example? I think not. Also, as flying slug said earlier, the first thing I noticed for your post was no pictures. Even without pictures this post still explains everything that needs explaining. Without the pictures the post is a little shorter, which is always a plus. Despite not having pictures, it is still also entertaining. Good job.<br /><br />Thanks,<br />mc Caspermc Casperhttps://www.blogger.com/profile/11740006144235430482noreply@blogger.comtag:blogger.com,1999:blog-3862070466581846873.post-11253916850000179902010-01-31T20:23:45.806-07:002010-01-31T20:23:45.806-07:00Blitzen, I used the exploration from class... And ...Blitzen, I used the exploration from class... And my grey box. Both were helpfulJ-tron foteenhttps://www.blogger.com/profile/12169811267606736921noreply@blogger.comtag:blogger.com,1999:blog-3862070466581846873.post-15369540338656624302010-01-31T20:00:33.319-07:002010-01-31T20:00:33.319-07:00This is a really thorough scribe post! It covered ...This is a really thorough scribe post! It covered everything we did in class, some subjects like explicit functions I had even forgotten already! But now I remember so thanks. Also it didn't seem like you rushed through it at all, the explanations are easy to understand and colorful! What resources did you use to make sure you covered all the material from class?blitzenhttps://www.blogger.com/profile/02942728397445326838noreply@blogger.comtag:blogger.com,1999:blog-3862070466581846873.post-51885396186738075962010-01-31T19:25:27.640-07:002010-01-31T19:25:27.640-07:00I thought that this post was quite good, I liked t...I thought that this post was quite good, I liked the formatting. At my first glance I was going to say that there should be more graphics, but once I read through the whole thing I don't think that it needed any graphics. Sometimes pictures can distract from the meaning of the actual post. I got a little confused when I started reading the procedure to find the derivative of the equation. A little confusion is inevitable though, and I think that you did a very good job describing what was going on. The large gap at the bottom of the post threw me off a little, but I got over that quickly. A job very well done.flying slughttps://www.blogger.com/profile/07817015602372891184noreply@blogger.comtag:blogger.com,1999:blog-3862070466581846873.post-35722294780327872542010-01-31T15:36:12.293-07:002010-01-31T15:36:12.293-07:00Hey J-Tron Foteen! I really enjoyed reading your s...Hey J-Tron Foteen! I really enjoyed reading your scribe post. The colors and the spaces left in between paragraphs made it easy to understand. <br />Everything was is detailed, like the steps used to solve the given problems. It was also helpful to include the solution of that homework problem in your post.<br /><br />aand, YDplus: that's a very complex one! Wow! where did you get that from? anyways, here is how I did it: <br /><br />[(sin(y)cos(xy))^6] xy = 10x <br /><br />{sin(y)}^6 {cos(xy)}^6 = 10(x^2)y<br /><br />6{sin(y)}^5 . cos(y) . y'. -6{cos(xy)}^5 . sin(xy) . (y+xy') = 10(2xy + x^2 .y')<br /><br />{-36[sin(y) . cos(xy)]^5 . cos(y) . sin(xy)} - 20xy = (x^2 . y') / [(y+xy') y']<br /><br /><br />{-36[sin(y) . cos(xy)]^5 . cos(y) . sin(xy)} - 20xy = x^2 / (y+xy')<br /><br />1/[{-36[sin(y) . cos(xy)]^5 . cos(y) . sin(xy)} - 20xy] = (y+xy') / x^2 <br /><br />y + xy' = x^2 /[{-36[sin(y) . cos(xy)]^5 . cos(y) . sin(xy)} - 20xy]<br /><br />xy' = [x^2 /[{-36[sin(y) . cos(xy)]^5 . cos(y) . sin(xy)} - 20xy]] - y<br /><br />y' = {[x^2 /[{-36[sin(y) . cos(xy)]^5 . cos(y) . sin(xy)} - 20xy]] - y}/x<br /><br />OMG! is there any way to do solve this problem in a short period of time? I feel like there should be, but I can't figure it out... <br />By the way, thanks YDplus for reminding me all of these rules.! :)Marleyhttps://www.blogger.com/profile/00933612052368318411noreply@blogger.comtag:blogger.com,1999:blog-3862070466581846873.post-78297586559342575242010-01-29T16:21:48.565-07:002010-01-29T16:21:48.565-07:00HI J-Tron Foteen,
Haha, I'm the first who co...HI J-Tron Foteen,<br /> Haha, I'm the first who commends on this post. Lucky!!!<br /> I like this post. It is well organized. I like the color to highlight the critical parts. A little review of the quiz at the very beginning is good. A lot of details provide people a better sense of explicit form and implicit form. By the way, I think the first question on the quiz has another solution. It is pretty obvious that the function appeared in the group is f(x) = x^ (-1/2). So we can use the power rule to figure out the derivative of this function and find the exact value of the derivative of the function at x = 1. Algebra is actually a very neat thing to master. I like doing algebra a lot. And algebra can always give you a better sense of math. That’s what I think, maybe not that relevant. <br /> One thing I think you probably want to add into your post is that when you are trying to find the derivative of a very complex function, don’t forget to use the other rules such as product rule. Another thing is that y can be in the y’. So people don’t need to find the explicit form of a very complex function to try to put y’ in terms of x. you can just leave y in the y’. <br /> By the way, if the function is ((sin(y)cos(xy))^6)/xy = 10x, can you find the derivative? Really complex……..YDplusSBhttps://www.blogger.com/profile/03133765178448567641noreply@blogger.com