1. For any function that is invertible, the derivative of the inverse of a function at a point is equal to one over the derivative of inverse of the original function.

2.

3.

Is volume an invertible function?

Yes Volume is an invertible function.

4.

5. Using the online graphing tool (right sidebar) or another graphing tool, plot the following four graphs:

(1)

(2)

(3)

(4)

6. I found the derivative of (1,4/3pi) and then (4/3pi,1), yielding slopes of 12.566 and 1/12.566. The slopes of the two tangents are recipricols of one another.

7. I decided to come to class due in large part to the fact that I felt that I would benefit the most from being able to participate in my education in person and would be able to activitly pursue and ask questions of what we were doing and how to do them. As well I felt if necessary the web material, the virtual classroom would be avialable to me after class to furhter expand upon my knowledge.

2.

3.

Is volume an invertible function?

Yes Volume is an invertible function.

4.

5. Using the online graphing tool (right sidebar) or another graphing tool, plot the following four graphs:

(1)

(2)

(3)

(4)

6. I found the derivative of (1,4/3pi) and then (4/3pi,1), yielding slopes of 12.566 and 1/12.566. The slopes of the two tangents are recipricols of one another.

7. I decided to come to class due in large part to the fact that I felt that I would benefit the most from being able to participate in my education in person and would be able to activitly pursue and ask questions of what we were doing and how to do them. As well I felt if necessary the web material, the virtual classroom would be avialable to me after class to furhter expand upon my knowledge.

Winn Plot,

ReplyDeletegreat post. This was neat, understandable, and easy to follow. You did a great job using equation editor and everything was covered thoroughly.

I also chose to come to class for the same reason, but will leave you with a question that I have been pondering; you said that you wanted to attend class to ask questions and actively participate, knowing the web material would be there if you needed it. But wouldn't the same apply if you chose to not attend class. Bru is always around to answer questions, and the scribe posts are pretty solid if you really needed the extra review. Wouldn't not going to class, if you can always email or ask Bru questions outside of class, allow you to actively participate just as much but get the class time to be productive in other ways?

Nice job on this forum post Winn Plot. I chose to do the same regarding the virtual classroom. I think being in class provides less distractions (knowing me, I don't last too long online without finding something that completely diverts my attention). While this was a very well done post, I think that cleaning up your graph might make it easier to understand. Labeling the lines with colors instead of numbers could help with understanding, and while it doesn't matter to the rest of class because we all know exactly what your talking about, others who maybe don't understand this might have a harder time reading it.

ReplyDeleteGreat Job!

HI Winn Plot,

ReplyDeleteGreat Job on every question you answered. I don’t see any errors or problems. You did a great job on using the equation editor. You did a great job on doing the plot, too. One thing I am pretty curious is that how long it took you to finish this post. I spent almost 2 hours on the plot thing. I think they definitely need an instruction in that website. They probably have, but I didn’t see. And another trick I don’t know if you realized is that you can put pi just as pi in the equation for that online graphing tool. So you don’t need to use the 3.14, this approximate number.

I chose to come to class too on that day. But my reason was a kind of stupid. I totally forgot that we had the choice to come to class. Until I found there were only 4 people in the classroom, I realized, oh, we are having a virtue class today. And actually, I feel it is just my custom to go to class in the weekday. I think if I study on my own, I would miss some critical parts. Teacher knows how to organize stuff better than we do. Anyway, good job.

Hey, I'm a little confused by the equation in your first statement. The left side is f inverse of x, but you are making a statement about the derivative of f inverse, right? Just checking. The right side has something funky going on with the parentheses. I think that there might be a wording problem in your first statement too. You say "one over the derivative of inverse of the original function" Do you really mean derivative of the original function's inverse (I think that's what you are saying). Here your equation says the take the derivative of the original function, then plug in f inverse of the point to the derivative.

ReplyDeleteJust making sure I've got this right.